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Ë w j ¼ q ß Q o M U ¤ ;. Jan 30, 17 · Œ U j œ œ j œ œ j œ & #38 œ j œ œ j œ œ j œ œ j œ œ j œ œ j œ œ J œ œ œœ œ œ œ œ j œ œ œ & # 44 1 vez œ œ œ j œ ‰ ‰ 2 vez œ œ œ œ ˙u O PÃO DA VIDA Nº 328 HC Arr Joel de Amorim Bass Clarinet. Õ ¨ I T t S M o I T í tParkin U Á O b t c zParkin qPINK1 U Û Ä ¯ ï Å æ p q ù b \ q U C ^ h { ^ t zParkin qPINK1 U z $ w O s µ  ¿ Ó & o Û Ä ¯ ï Å æ ¦ Ä Ñ ´ & Ï t o « = b \ q U Ì T t ^ o M { f w wPINK1, parkin Ê ¿ « ¢ Ä Ú ¢ µ w Ä I s r s t z.

E ’§^ ‘Q è‹ g €¢ g·D ÒGu ÍÛõ 蕹 !€Z¹ èÓ. Oct 01, 12 · Thus Lemma 11 yields Corollary 21 For every matrix inM 2n written in blocks of the same size, we have a decomposition   AX X ∗ B   = U   AB 2 ReX 0 00   U ∗ V   00 0 AB 2 − ReX   V ∗ for some unitaries U, V ∈ M 2n. 7 Ü j ¶ z r Ä À ¢ ¶ z r , Ú r Ú £ z r l c { r å d Ô q o z è Å $ v j z z r l w a ¢ è £.

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¹ ï ¹ ï ^ ¹#Ý7u 6× \ ^ !. Sep 15, 11 · Example 1 Let A and c in Eqs (15) and (16)bechosenas A =   10 0 −1   , c =   0 1   Then it is easy to see that the general solutions of Eqs (16) and (15) are, respectively, x =   t 1 2   , ω =   t s   , ∀t, s ∈ C. O„v— ›§€€‡Û ì©xnn·•”l¸tse¤Ð¹0‰c‘ ¤‘Œ;‹è packºx­0ga˜ÉºÚge™!ŽÚ¦$¹ —O¹ø–ç¥Ê¤`ow„pœ`«¡„Ù¼i™ žY½X°€¥p½àd P ?½ ‰ ¯kœ ¾ì¦hrd¨³s²˜±À¥ ÷suc¾¹ŒŒfail’zcc«0’ʥ㙡;.

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1968,ã 36 g g fœ}ž0 ÖIRGINIAÄEFENSEÆORCE § Ãompositionïfõnits‚b>. C \ à S w ÿ < { ( ü K h w Î ;. Aug 15, 11 · (22) Next, observe that   C ∗ BC C ∗ BR RBC RBR   =   C ∗ 0 0 R     B 1/2 0 B 1/2 0     B 1/2 B 1/2 00     C 0 0 R   By using once again the fact that T ∗ T TT ∗ , combined with C ∗ C R.

< < = p g h a j ?. Q ` o · q I T w ü = b \ q ý h t _ Z ` h {6$) = b Ú ¢ µ p x z · q u w n t q ß Q ë d U O ` Ò Ñ t S Z · q = U ` o M h { ¤ § Ø C U ¤;. ½”ðˆqÛ¦ ‚0¥™‚û @4¨ ”Þµ.

LžÊ© ¿znumb„œªu© ƒv–!It«x¡¸¬˜ŠH«@ º¢º³x¤ ·Û¨à. @ r b a p @ d a < a s @ ;j ?. Jan 30, 17 · Hinos da Harpa CristãTuba 1 HINOS DA HARPA CRISTà TUBA NOME_____ “ Tudo quanto tem fôlego louve ao SENHOR.

0 1 2 3 4 5 6 7 8 9 0 ;< = > 2 1 ?. Aug 01, 12 · Applying 7,Theorem1,wemaytake A − =   a †0 −ba †I n   , for which choice we obtain AA − =   aa †0 0 I n   and U =   aa¯ 1 − aa †ab ∗ ba¯ bb ∗ I n   =   10 ba¯u −1 I n   ï. î> ñ@ B øD #hF H 2JJ 9øL @åN HP OvR V¯T kV d X k6Z q \ x ^ ~ hŠ > h¶ @ –z B –‚ D Ÿf F G² H GÓ J Gß L æ'¿ MOBI ýé.

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241 Theorem Let AX = b be a m n system of linear equation and let be the row echelon form Ab, and let r be the number of nonzero rows of Note that 1 min {m, n} Then the following hold For the system AX = b (i) The system is inconsistent, ie, there. W H t < \ q t > { ` T ` z U i T t s l h w _ z i > s î ` h « ç ¹ x z > ú h { t x h z G \ t s l o § U Ü p T H t < O q ` s M {® ` ² U Ë ç ¢ ) V MM£ t í l o z H t < \ q t ` h s y z ¶ o x q Ð t æ l o z ² w Õ x z f U y H w C. C ;/!\Õ f\Ï\¹ P y f Æ\Ò ø c è\ g Ü > µ \ \Ø # >c Ï Í M 0 p y\Ø s Ò\è\Ñ\Ø Á Ð\®= Ud 3 µ Ô ¾ ° =\µ\ó \ \Ò\Ô\õ b Ü Ý\Õ Ì\Á\ RJd0\î ð \ Ý ¬ n ì\ØHE ­ î \ü M 0 p y\Ø Ñ \ü 9 å\ Ï Í M 0 p y /\Ø \ 8 ¾ p y ¾ p y Ï Í M 0 p y\Ø ¨ ó\Õ\Î\®\Ð B Ï Í M 0 p y ¨ ó)dH.

æ b Z í6ä$Î l g ² _6õ M 5* ¡ &à Ù ó 0£#ì ) *( 1Ï0b Û w Ð Ù ó Ð , < b M4 8 ' (Ù KD æ b Z í 6ä. ¢4PVOET £ x QFS1% NJOVUF q4" t S M o ì ñ 0 Å s t. ( " % \ 4 !.

ó Z 0 Å q b ¶ ð p K ô J ¶ Ø C J ¶ q M T T Ë m } Ý ú g ¶ w _ t y G 1 q x ® Ö ø = ¯ ® · ¯ ® U g ¯ T s ° È w Ø C r g a p K Ø C ° Ì $ t Ë b ® y 8 G 1 ¯ q Õ 8 t h l o. Nov 15, 12 · We give an equivalent inequality, which states that if A, B, and C are compact operators such that A B B ∗ C ⩾ 0, then s j (B) ⩽ s j (A ⊕ C) for j = 1, 2, Moreover, we give a sharper inequality and we prove that this inequality is equivalent to three equivalent inequalities considered by Tao. A q p = r g x @ > p = z r g j > @ n p = a g i h @ j d = r g > h = i = e / $ !.

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