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I don't see how to do it with with proof by cases I would do it by expanding the set operations into set builder definitions itex\left(A \cup B \right) \left( A \cup B \right) = \left\{ a \left( a \in A \vee a \in B \right) \wedge \neg \left( a \in A \wedge a \in B \right) \right\} /itex and itex\left( AB \right) \cup \left( BA \right) = \left\{ a \left( a \in A \wedge a \notin. 3 0$ Âœ4{ 5ÃB N Ô y â. 2701Misc 8 Introduction Show that for any sets A and B, A = (A ∩ B) ∪ (A – B) and A ∪ (B – A) = (A ∪ B) Let U = {1, 2, 3, 4, 5} A = {1, 2} B = {2, 3, 4} A.

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